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Q. The sum of coefficients in the expansion of $(1 + 3x -3x^2)^{1143}$ is equal to

KEAMKEAM 2012Binomial Theorem

Solution:

Given expansion is $\left(1+3 x-3 x^{2}\right)^{1143}$
Put $x=1$, we get
$\left[1+3 \times 1-3(1)^{2}\right]^{1143} =[1+3-3]^{1143} $
$=(1)^{1143}=1 $