Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The strength of 11.2 volume solution of H2O2 is: [Given that molar mass of H = 1 g mol-1 and O = 16 g mol-1]
Q. The strength of
11.2
volume solution of
H
2
O
2
is : [Given that molar mass of
H
=
1
g
m
o
l
−
1
and
O
=
16
g
m
o
l
−
1
]
3027
201
JEE Main
JEE Main 2019
Hydrogen
Report Error
A
13.6%
7%
B
3.4%
88%
C
34%
5%
D
1.7%
0%
Solution:
68
g
/
L
2
H
2
O
2
⟶
2
H
2
O
+
22.4
of
O
2
(
STP
)
O
2
↑
11.2
L
of
O
2
is given by
34
g
of
H
2
O
2
present in
1
L
of
H
2
O
2
solution.
So
%
strength of
H
2
O
2
=
1000
34
×
100
=
3.4
g
/100
m
L
=
3.4%