Question

The strength of $11.2$ volume solution of $H_2O_2$ is : [Given that molar mass of $H = 1\, g$ $mol^{-1}$ and $O = 16\, g\, mol^{-1}]$

• A. $13.6\%$
• B. $3.4\%$
• C. $34\%$
• D. $1.7\%$

Answer 1

Answer: (B)

$\underset{68 g / L }{2 H _{2} O _{2}} \longrightarrow 2 H _{2} O +\underset{22.4 \,\,\text{of}\,\, O_{2}( STP )}{ O _{2} \uparrow}$
$11.2 \,L$ of $O _{2}$ is given by $34 \,g$ of $H _{2} O _{2}$ present in $1 \,L$ of $H _{2} O _{2}$ solution.
So $\%$ strength of $H _{2} O _{2}=\frac{34}{1000} \times 100=3.4 \,g / 100 \,mL =3.4 \%$