Question

The STP volume of oxygen liberated by $2A$ of current when passed through acidulated water for $3$ min and $13s$ is

• A. 120 cc
• B. 22.4 cc
• C. 11.2cc
• D. 44.8 cc

Answer 1

Answer: (B)

$2H_{2}O\rightleftharpoons 4H^{+}+2O^{2-}$

$\because 4\times 96500C$ electricity liberate $O_2$
$=22400cc$
$\therefore (2\times 193)C$ electricity will liberate $O_2$
$=\frac{22400\times 386}{4\times 96500}$
$=22.4cc$