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  4. The STP volume of oxygen liberated by 2 A of current when passed through acidulated water for 3 min and 13 s is

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Q. The STP volume of oxygen liberated by $2\, A $ of current when passed through acidulated water for $3$ min and $13\, s$ is

BHUBHU 2010

Solution:

$2 H _{2} O \rightleftharpoons 4 H ^{+}+2 O ^{2-}$
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$\because 4 \times 96500\, C$ electricity liberate $O _{2}$
$=22400\, cc$
$\therefore (2 \times 193) \,C$ electricity will liberate $O _{2}$
$=\frac{22400 \times 386}{4 \times 96500}$
$=22.4 \,cc$