The standard electrode potential (E°) for OCl-/ Cl- and Cl-/ (1/2) Cl2 respectively are 0.94 V and -1.36 V . The E° value for O Cl-/ (1/2)C l2 will be

Question

The standard electrode potential (E°) for OCl-/ Cl- and Cl-/ (1/2) Cl2 respectively are 0.94 V and -1.36 V . The E° value for O Cl-/ (1/2)C l2 will be (A)  - 0.42 V  (B)  -2.20 V  (C)  0.52 V  (D)  1.04 V

Tardigrade Admin · Accepted Answer

Given, (i) OCl - longrightarrow Cl - E°=0.94 V (i) Cl - longrightarrow (1/2) Cl 2+e- E°=-1.36 V To get OCl - longrightarrow (1/2) Cl 2 Eq. (i) + Eq. (ii), OCl - longrightarrow (1/2) Cl 2+e- E°=(0.94-1.36) =-0.42 V

Q. The standard electrode potential $(E^{\circ})$ for $OC l^{-} / C l^{-}$ and $C l^{-} / \frac{1}{2} C l_{2}$ respectively are $0.94 V$ and $- 1.36 V$ . The $E^{\circ}$ value for $OC l^{-} / \frac{1}{2} C l_{2}$ will be

$- 0.42 V$

$- 2.20 V$

$0.52 V$

$1.04 V$

Given,

(i) $OC l^{-} ⟶ C l^{-} E^{\circ} = 0.94 V$

(i) $C l^{-} ⟶ \frac{1}{2} C l_{2} + e^{-} E^{\circ} = - 1.36 V$

To get $OC l^{-} ⟶ \frac{1}{2} C l_{2}$

Eq. (i) + Eq. (ii),

$OC l^{-} ⟶ \frac{1}{2} C l_{2} + e^{-} E^{\circ} = (0.94 - 1.36)$

$= - 0.42 V$

Q. The standard electrode potential (E∘) for OCl−/Cl− and Cl−/21​Cl2​ respectively are 0.94V and −1.36V . The E∘ value for OCl−/21​Cl2​ will be

−0.42V

−2.20V

0.52V

1.04V