The spin only magnetic moment of Fe2+ ion (in B.M.) is approximately

Question

The spin only magnetic moment of Fe2+ ion (in B.M.) is approximately (A) 4 (B) 7 (C) 5 (D) 6

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fe83835ed8a6f68bcd732758c0799340-.png" /> It has 4 unpaired electrons ∴ μ =√n(n+2) =√4(4+2) =√24 μ =4.89 BM ≈ 5 BM

Q. The spin only magnetic moment of $F e^{2 +}$ ion $(in B . M .)$ is approximately

4

7

5

6

It has 4 unpaired electrons

$∴ μ = n (n + 2)$

$= 4 (4 + 2)$

$= 24$

$μ = 4.89 BM \approx 5 BM$

Q. The spin only magnetic moment of Fe2+ ion (inB.M.) is approximately

4

7

5

6

It has 4 unpaired electrons ∴μ=n(n+2)​ =4(4+2)​ =24​ μ=4.89BM≈5BM

Q. The spin only magnetic moment of $F e^{2 +}$ ion $(in B . M .)$ is approximately

It has 4 unpaired electrons

$∴ μ = n (n + 2)$

$= 4 (4 + 2)$

$= 24$

$μ = 4.89 BM \approx 5 BM$