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Q. The spin only magnetic moment of $Fe^{2+}$ ion $(in\, B.M.)$ is approximately

KCETKCET 2011The d-and f-Block Elements

Solution:

image

It has 4 unpaired electrons

$\therefore \mu =\sqrt{n(n+2)}$

$=\sqrt{4(4+2)}$

$=\sqrt{24}$

$\mu =4.89\, BM\, \approx 5\, BM$