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Chemistry
The spin only magnetic moment of Fe2+ ion (in B.M.) is approximately
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Q. The spin only magnetic moment of $Fe^{2+}$ ion $(in\, B.M.)$ is approximately
KCET
KCET 2011
The d-and f-Block Elements
A
4
30%
B
7
10%
C
5
46%
D
6
15%
Solution:
It has 4 unpaired electrons
$\therefore \mu =\sqrt{n(n+2)}$
$=\sqrt{4(4+2)}$
$=\sqrt{24}$
$\mu =4.89\, BM\, \approx 5\, BM$