The speed of light in media ' A ' and ' B ' are 2.0 × 1010 cm / s and 1.5 × 1010 chm / s respectively. A ray of light enters from the medium B to A at an incident angle ' θ '. If the ray suffers total internal reflection, then

Question

The speed of light in media ' A ' and ' B ' are 2.0 × 1010 cm / s and 1.5 × 1010 chm / s respectively. A ray of light enters from the medium B to A at an incident angle ' θ '. If the ray suffers total internal reflection, then (A) θ= sin -1((3/4)) (B) θ > sin -1((2/3)) (C) θ< sin -1((3/4)) (D) θ > sin -1((3/4))

Tardigrade Admin · Accepted Answer

sin i c =( n r / n d )=( C d / C r )=(1.5 × 1010/2 × 1010) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a3383535e32130cdee22de0a955bdf10-.png" /> sin ic=(3/4) ic= sin -1((3/4)) for T I R θ>ic θ> sin -1((3/4))

Q. The speed of light in media ' $A$ ' and ' $B$ ' are $2.0 \times$ $1 0^{10} c m / s$ and $1.5 \times 1 0^{10} c hm / s$ respectively. A ray of light enters from the medium $B$ to $A$ at an incident angle ' $θ$ '. If the ray suffers total internal reflection, then

$θ = sin^{- 1} (\frac{3}{4})$

$θ > sin^{- 1} (\frac{2}{3})$

$θ < sin^{- 1} (\frac{3}{4})$

$θ > sin^{- 1} (\frac{3}{4})$

$sin i_{c} = \frac{n _{r}}{n _{d}} = \frac{C _{d}}{C _{r}} = \frac{1.5 \times 1 0 ^{10}}{2 \times 1 0 ^{10}}$

$sin i_{c} = \frac{3}{4}$
$i_{c} = sin^{- 1} (\frac{3}{4})$
for T I R $θ > i_{c}$
$θ > sin^{- 1} (\frac{3}{4})$

Q. The speed of light in media ' A ' and ' B ' are 2.0× 1010cm/s and 1.5×1010chm/s respectively. A ray of light enters from the medium B to A at an incident angle ' θ '. If the ray suffers total internal reflection, then

θ=sin−1(43​)

θ>sin−1(32​)

θ<sin−1(43​)

θ>sin−1(43​)