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Q. The speed of light in media ' $A$ ' and ' $B$ ' are $2.0 \times$ $10^{10} cm / s$ and $1.5 \times 10^{10} chm / s$ respectively. A ray of light enters from the medium $B$ to $A$ at an incident angle ' $\theta$ '. If the ray suffers total internal reflection, then

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Solution:

$\sin i _{ c }=\frac{ n _{ r }}{ n _{ d }}=\frac{ C _{ d }}{ C _{ r }}=\frac{1.5 \times 10^{10}}{2 \times 10^{10}}$
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$\sin i_{c}=\frac{3}{4}$
$i_{c}=\sin ^{-1}\left(\frac{3}{4}\right)$
for T I R $ \theta>i_{c}$
$\theta>\sin ^{-1}\left(\frac{3}{4}\right)$