The specific conductivity of 0.1 N KCl solution is 0.0129 ohm -1 cm -1. The resistance of the solution in the cell is 100 ohm. The cell constant of the cell will be

Question

The specific conductivity of 0.1 N KCl solution is 0.0129 ohm -1 cm -1. The resistance of the solution in the cell is 100 ohm. The cell constant of the cell will be (A) 1.10 (B) 1.29 (C) 0.56 (D) 2.80

Tardigrade Admin · Accepted Answer

Specific conductivity ( K )=(1/ R ) × Cell constant Cell constant = K × R =0.0129 × 100=1.29

Q. The specific conductivity of $0.1 N K Cl$ solution is $0.0129 o h m^{- 1} c m^{- 1}$ . The resistance of the solution in the cell is $100 o hm$ . The cell constant of the cell will be

1.10

1.29

0.56

2.80

Specific conductivity $(K) = \frac{1}{R} \times$ Cell constant
Cell constant $= K \times R = 0.0129 \times 100 = 1.29$

Q. The specific conductivity of 0.1NKCl solution is 0.0129ohm−1cm−1. The resistance of the solution in the cell is 100ohm. The cell constant of the cell will be