1. Tardigrade
  2. Question
  3. Chemistry
  4. The specific conductivity of 0.1 N KCl solution is 0.0129 ohm -1 cm -1. The resistance of the solution in the cell is 100 ohm. The cell constant of the cell will be

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Q. The specific conductivity of $0.1\, N\, KCl$ solution is $0.0129\, ohm ^{-1} cm ^{-1}$. The resistance of the solution in the cell is $100\, ohm$. The cell constant of the cell will be

ManipalManipal 2019

Solution:

Specific conductivity $( K )=\frac{1}{ R } \times$ Cell constant
Cell constant $= K \times R =0.0129 \times 100=1.29$