The specific conductance of a N/10 KCl at 25° C is 0.0112 ohm-1 cm-1 . The resistance of cell containing solution at the same temperature was found to be 55 ohms. The cell constant will be

Question

The specific conductance of a N/10 KCl at 25° C is 0.0112 ohm-1 cm-1 . The resistance of cell containing solution at the same temperature was found to be 55 ohms. The cell constant will be (A) 6.16 cm -1 (B) 0.616 cm -1 (C) 0.0616 cm -1 (D) 616 cm -1

Tardigrade Admin · Accepted Answer

We known that specific conductance = Cell constant × conductance ⇒ Cell constant = Resitances × sp. conductance =55 × 0.0112 =0.616 cm -1

Q. The specific conductance of a $N /10 K Cl$ at $2 5^{\circ} C$ is $0.0112 o h m^{- 1} c m^{- 1}$ . The resistance of cell containing solution at the same temperature was found to be $55$ ohms. The cell constant will be

$6.16 c m^{- 1}$

$0.616 c m^{- 1}$

$0.0616 c m^{- 1}$

$616 c m^{- 1}$

We known that

specific conductance = Cell constant $\times$ conductance

$\Rightarrow$ Cell constant = Resitances $\times$ sp. conductance

$= 55 \times 0.0112$

$= 0.616 c m^{- 1}$

Q. The specific conductance of a N/10KCl at 25∘C is 0.0112ohm−1cm−1 . The resistance of cell containing solution at the same temperature was found to be 55 ohms. The cell constant will be

6.16cm−1

0.616cm−1

0.0616cm−1

616cm−1