The solution of the following equations: x - (4k - 3)y + 2z = 0 kx - (2k - 1)y + (k + 1) z = 0 (2k + 2) x + 3ky + (k + 2) z = 0 for k = 1 , (x, y, z) is given by

Question

The solution of the following equations: x - (4k - 3)y + 2z = 0 kx - (2k - 1)y + (k + 1) z = 0 (2k + 2) x + 3ky + (k + 2) z = 0 for k = 1 , (x, y, z) is given by (A) (t, 3t, t) (B) (-2t, - 10t , - 4t) (C) (9t , - 5t , - 7t) (D) (4t , 6t, t )

Tardigrade Admin · Accepted Answer

Correct answer is (c) (9t , - 5t , - 7t)

Q. The solution of the following equations:
$x - (4 k - 3) y + 2 z = 0$
$k x - (2 k - 1) y + (k + 1) z = 0$
$(2 k + 2) x + 3 k y + (k + 2) z = 0$
for $k = 1, (x, y, z)$ is given by

$(t, 3 t, t)$

$(- 2 t, - 10 t, - 4 t)$

$(9 t, - 5 t, - 7 t)$

$(4 t, 6 t, t)$

Correct answer is (c) $(9 t, - 5 t, - 7 t)$

Q. The solution of the following equations: x−(4k−3)y+2z=0 kx−(2k−1)y+(k+1)z=0 (2k+2)x+3ky+(k+2)z=0 fork=1,(x,y,z) is given by

(t,3t,t)

(−2t,−10t,−4t)

(9t,−5t,−7t)

(4t,6t,t)