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Q. The solution of the following equations:
$x - (4k - 3)y + 2z = 0$
$kx - (2k - 1)y + (k + 1) z = 0$
$(2k + 2) x + 3ky + (k + 2) z = 0$
for$ k = 1 , (x, y, z)$ is given by

Determinants

Solution:

Correct answer is (c) $(9t , - 5t , - 7t)$