Q.
The solution of the following equations:
$x - (4k - 3)y + 2z = 0$
$kx - (2k - 1)y + (k + 1) z = 0$
$(2k + 2) x + 3ky + (k + 2) z = 0$
for$ k = 1 , (x, y, z)$ is given by
Determinants
Solution: