Question

The solution of the equation $2x^3-x^2-22x-24=0$ when two of the roots are in the ratio $3:4,$ is

• A. $3,4,\frac{1}{2}$
• B. $-\frac{3}{2},-2,4$
• C. $-\frac{1}{2},\frac{3}{2},2$
• D. $\frac{3}{2},2,\frac{5}{2}$

Answer 1

Answer: (B)

Given equation is
$2x^3-x^2-22x-24=0$
On putting
$x=0,1,-1,2,-2$ only $x=-2$
satisfies this equation.
So, $x=-2$
is a root of this equation and from the given options only [b] has this root.