Question

The solution of the equation $ 2{{x}^{3}}-{{x}^{2}}-22x-24=0 $ when two of the roots are in the ratio $ 3:4, $ is

• A. $ 3,\,4,\frac{1}{2} $
• B. $ -\frac{3}{2},-2,4 $
• C. $ -\frac{1}{2},\frac{3}{2},2 $
• D. $ \frac{3}{2},2,\frac{5}{2} $

Answer 1

Answer: (B)

Given equation is
$ 2{{x}^{3}}-{{x}^{2}}-22x-24=0 $
On putting
$ x=0,1,-1,2,-2 $ only $ x=-2 $
satisfies this equation.
So, $ x=-2 $
is a root of this equation and from the given options only [b] has this root.