Question

The solution of nickel sulphate, in which a nickel rod is dipped, has been diluted $10$ times. The potential of the nickel electrode

• A. decreases by 60 mV
• B. increases by 30 mV
• C. decreases by 30 mV
• D. increases by 60 mV

Answer 1

Answer: (C)

$N{i}^{2+}+2e^{-}\to Ni(s)$

$E=E^{\circ }-\frac{0.059}{2}\log$

After dilution, $E=E^{\circ }-\frac{0.059}{2}\log \frac{10}{x}$

Therefore, the potential decreases by $\frac{0.059}{2}\log 10=0.0295$

$V$ or $0.03V$ or $30.0mV$