Question

The solution of nickel sulphate, in which a nickel rod is dipped, has been diluted $10$ times. The potential of the nickel electrode

• A. decreases by 60 mV
• B. increases by 30 mV
• C. decreases by 30 mV
• D. increases by 60 mV

Answer 1

Answer: (C)

$Ni ^{2+}+2 e^{-} \rightarrow Ni ( s ) $

$E =E^{\circ}-\frac{0.059}{2} \log$

After dilution, $E=E^{\circ}-\frac{0.059}{2} \log \frac{10}{x}$

Therefore, the potential decreases by $\frac{0.059}{2} \log 10=0.0295$

$V$ or $0.03\, V$ or $30.0\, mV$