The solubility product of Ni ( OH )2 is 2.0 × 10-15. The molar solubility of Ni ( OH )2 in 0.1 M NaOH solution is

Question

The solubility product of Ni ( OH )2 is 2.0 × 10-15. The molar solubility of Ni ( OH )2 in 0.1 M NaOH solution is (A) 1.0 × 10-5 (B) 2.0 × 10-13 M (C) 4.44 × 10-8 M (D) 2.0 × 10-12 M

Tardigrade Admin · Accepted Answer

S=(Ks p/[ OH -]2)=(2 × 10-15/(0.1)2)=2 × 10-13

Q. The solubility product of $N i (O H)_{2}$ is $2.0 \times 1 0^{- 15}$ . The molar solubility of $N i (O H)_{2}$ in $0.1 M N a O H$ solution is

$1.0 \times 1 0^{- 5}$

$2.0 \times 1 0^{- 13} M$

$4.44 \times 1 0^{- 8} M$

$2.0 \times 1 0^{- 12} M$

$S = \frac{K _{s p}}{[ O H ^{-} ] ^{2}} = \frac{2 \times 1 0 ^{- 15}}{( 0.1 ) ^{2}} = 2 \times 1 0^{- 13}$

Q. The solubility product of Ni(OH)2​ is 2.0×10−15. The molar solubility of Ni(OH)2​ in 0.1MNaOH solution is

1.0×10−5

2.0×10−13M

4.44×10−8M

2.0×10−12M