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Q. The solubility product of $Ni ( OH )_2$ is $2.0 \times 10^{-15}$. The molar solubility of $Ni ( OH )_2$ in $0.1 \,M \,NaOH$ solution is

NEETNEET 2022Equilibrium

Solution:

$S=\frac{K_{s p}}{\left[ OH ^{-}\right]^2}=\frac{2 \times 10^{-15}}{(0.1)^2}=2 \times 10^{-13}$