Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The solubility of calomel in water at 25°C is x moles/litre. Its solubility product is
Q. The solubility of calomel in water at
2
5
∘
C is
x
moles/litre. Its solubility product is
1518
225
Equilibrium
Report Error
A
4
x
3
33%
B
12
x
3
11%
C
108
x
5
56%
D
x
2
0%
Solution:
H
g
2
C
l
2
⇌
x
H
g
2
+
2
+
2x
2
C
l
−
K
s
p
=
[
H
g
2
+
2
]
[
C
l
−
]
2
=
(
x
)
(
2
x
)
2
=
4
x
3