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Q. The solubility of calomel in water at $25^\circ$C is $x$ moles/litre. Its solubility product is

Equilibrium

Solution:

$Hg_{2}Cl_{2} \rightleftharpoons \underset{\text{x}}{{Hg_{2}^{+2}}}+\underset{\text{2x}}{{2Cl^{-}}}$
$K_{sp}=[Hg^{+2}_{2}] [Cl^{-}]^{2}=(x)(2x)^{2}$
$=4x^{3}$