The solubility of BaSO4 in water is 2.33 × 10-3 gram/litre. Its solubility product will be (molecular weight of BaSO4 = 233)

Question

The solubility of BaSO4 in water is 2.33 × 10-3 gram/litre. Its solubility product will be (molecular weight of BaSO4 = 233) (A) 1 × 10-15 (B) 1 × 10-10 (C) 1 × 10-5 (D) 1 × 10-20

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a7f5e621663a8d07e62d683de8dcf67d-.png" /> ∴ Solubility Product =[ Ba 2+][ SO 42-] =s2 =(10-5)2 =10-10

Q. The solubility of $B a S O_{4}$ in water is $2.33 \times 1 0^{- 3}$ gram/litre. Its solubility product will be (molecular weight of $B a S O_{4} = 233$ )

$1 \times 1 0^{- 15}$

$1 \times 1 0^{- 10}$

$1 \times 1 0^{- 5}$

$1 \times 1 0^{- 20}$

$∴$ Solubility Product $= [B a^{2 +}] [S O_{4}^{2 -}]$

$= s^{2}$

$= (1 0^{- 5})^{2}$

$= 1 0^{- 10}$

Q. The solubility of BaSO4​ in water is 2.33×10−3 gram/litre. Its solubility product will be (molecular weight of BaSO4​=233)

1×10−15

1×10−10

1×10−5

1×10−20