Question

The solubility of $BaSO_4$ in water is $2.33 \times 10^{-3}$ gram/litre. Its solubility product will be (molecular weight of $BaSO_4 = 233$)

• A. $1 \times 10^{-15}$
• B. $1 \times 10^{-10}$
• C. $1 \times 10^{-5}$
• D. $1 \times 10^{-20}$

Answer 1

Answer: (B)

$\therefore $ Solubility Product $=\left[ Ba ^{2+}\right]\left[ SO _{4}^{2-}\right]$

$=s^{2}$

$=\left(10^{-5}\right)^{2}$

$=10^{-10}$