The solubility of AgCl in moles per litre when its solubility product is 1.56× 10-10 at 25°C is :

Question

The solubility of AgCl in moles per litre when its solubility product is 1.56× 10-10 at 25°C is : (A)  0.576× 10-8 mol/L  (B)  1.056× 10-4mol/L  (C)  1.249× 10-5L  (D)  1.478× 10-6mol/L

Tardigrade Admin · Accepted Answer

AgCl is a sparingly soluble salt. Let its solubility be s mol / L. AgCl leftharpoons undersetsAg ++ undersets Cl - Solubility product K sp K sp =s × s s=√K sp =√1.56 × 10-10 s=1.249 × 10-5 mol / L

Q. The solubility of $A g Cl$ in moles per litre when its solubility product is $1.56 \times 1 0^{- 10}$ at $2 5^{\circ} C$ is :

$0.576 \times 1 0^{- 8} m o l / L$

$1.056 \times 1 0^{- 4} m o l / L$

$1.249 \times 1 0^{- 5} L$

$1.478 \times 1 0^{- 6} m o l / L$

$A g Cl$ is a sparingly soluble salt. Let its solubility be $s m o l / L$ .
$A g Cl ⇌ s A g^{+} + s Cl^{-}$
Solubility product $K_{s p}$
$K_{s p} = s \times s$
$s = K_{s p} = 1.56 \times 1 0^{- 10}$
$s = 1.249 \times 1 0^{- 5} m o l / L$

Q. The solubility of AgCl in moles per litre when its solubility product is 1.56×10−10 at 25∘C is :

0.576×10−8mol/L

1.056×10−4mol/L

1.249×10−5L

1.478×10−6mol/L