Question

The solubility of $ AgCl $ in moles per litre when its solubility product is $ 1.56\times 10^{-10} $ at $ 25^{\circ}C $ is :

• A. $ 0.576\times 10^{-8}\,mol/L $
• B. $ 1.056\times 10^{-4}mol/L $
• C. $ 1.249\times 10^{-5}L $
• D. $ 1.478\times 10^{-6}mol/L $

Answer 1

Answer: (C)

$AgCl$ is a sparingly soluble salt. Let its solubility be $s\, mol / L$.
$AgCl \rightleftharpoons \underset{s}{Ag ^{+}}+\underset{s}{ Cl }^{-}$
Solubility product $K_{ sp }$
$K_{ sp }=s \times s $
$s=\sqrt{K_{ sp }}=\sqrt{1.56 \times 10^{-10}} $
$s=1.249 \times 10^{-5} mol / L$