The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10-5 mol L -1. Its solubility product number will be:

Question

The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10-5 mol L -1. Its solubility product number will be: (A) 4 × 10-15 (B) 4 × 10-10 (C) 1 × 10-15 (D) 1 × 10-10

Tardigrade Admin · Accepted Answer

AB2 leftharpoons undersetsA2++ underset2s2B- Ks p =[A2+][B]2 =(S)(2 S)2=4 S3 =4(1 × 10-5)3 =4 × 10-15

Q. The solubility in water of a sparingly soluble salt $A B_{2}$ is $1.0 \times 1 0^{- 5} m o l L^{- 1}$ . Its solubility product number will be:

$4 \times 1 0^{- 15}$

$4 \times 1 0^{- 10}$

$1 \times 1 0^{- 15}$

$1 \times 1 0^{- 10}$

$A B_{2} ⇌ s A^{2 +} + 2 s 2 B^{-}$

$K_{s p} = [A^{2 +}] [B]^{2}$

$= (S) (2 S)^{2} = 4 S^{3}$

$= 4 (1 \times 1 0^{- 5})^{3}$

$= 4 \times 1 0^{- 15}$

Q. The solubility in water of a sparingly soluble salt AB2​ is 1.0×10−5molL−1. Its solubility product number will be:

4×10−15

4×10−10

1×10−15

1×10−10