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Tardigrade
Question
Chemistry
The solubility in water of a sparingly soluble salt AB2 is 1.0 × 10-5 mol L -1. Its solubility product number will be:
Q. The solubility in water of a sparingly soluble salt
A
B
2
is
1.0
×
1
0
−
5
m
o
l
L
−
1
. Its solubility product number will be:
3932
206
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Equilibrium
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A
4
×
1
0
−
15
25%
B
4
×
1
0
−
10
28%
C
1
×
1
0
−
15
21%
D
1
×
1
0
−
10
26%
Solution:
A
B
2
⇌
s
A
2
+
+
2
s
2
B
−
K
s
p
=
[
A
2
+
]
[
B
]
2
=
(
S
)
(
2
S
)
2
=
4
S
3
=
4
(
1
×
1
0
−
5
)
3
=
4
×
1
0
−
15