Question

The slope of the graph between $\log P$ and $\log V$ at constant temperature for a given mass of a gas is

• A. $+1$
• B. $-1$
• C. $\frac{1}{T}$
• D. $\frac{1}{n}$

Answer 1

Answer: (B)

According to Boyle's law,
$P\propto \frac{1}{V}$
or, $P=\frac{k}{V}$
Applying log on both sides,
$\log P=\log k-\log V$
Comparing with $y=mx+c$
We get slope, $m=-1$