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  4. The slope of the graph between log P and log V at constant temperature for a given mass of a gas is

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Q. The slope of the graph between $\log P$ and $\log V$ at constant temperature for a given mass of a gas is

States of Matter

Solution:

According to Boyle's law,
$P \propto \frac{1}{ V }$
or, $P=\frac{k}{V}$
Applying log on both sides,
$\log P=\log k-\log V$
Comparing with $y=m x+c$
We get slope, $m=-1$