The slope of 'P' vs '1/V' plot at constant temperature for a fixed amount of the gas is 60 litre atm. Then the pressure in atm is

Question

The slope of 'P' vs '1/V' plot at constant temperature for a fixed amount of the gas is 60 litre atm. Then the pressure in atm is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4cfcb07f82f42a9dbdb2995a7ff6c4a2-.png" /> Boyle's law P=(K/V) Slope =K=601- atm P=(60/V)=(60/15)=4 atm.

Q. The slope of ' $P$ ' vs ' $1/ V$ ' plot at constant temperature for a fixed amount of the gas is $60$ litre atm. Then the pressure in atm is

Boyle's law $P = \frac{K}{V}$
Slope $= K = 601 - a t m$
$P = \frac{60}{V} = \frac{60}{15} = 4 a t m$ .

Q. The slope of 'P' vs '1/V' plot at constant temperature for a fixed amount of the gas is 60 litre atm. Then the pressure in atm is

Boyle's law P=VK​ Slope =K=601−atm P=V60​=1560​=4atm.

Q. The slope of ' $P$ ' vs ' $1/ V$ ' plot at constant temperature for a fixed amount of the gas is $60$ litre atm. Then the pressure in atm is

Boyle's law $P = \frac{K}{V}$
Slope $= K = 601 - a t m$
$P = \frac{60}{V} = \frac{60}{15} = 4 a t m$ .