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Q. The slope of '$P$' vs '$1/V$' plot at constant temperature for a fixed amount of the gas is $60$ litre atm. Then the pressure in atm is

States of Matter

Solution:

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Boyle's law $P=\frac{K}{V}$
Slope $=K=601- atm$
$P=\frac{60}{V}=\frac{60}{15}=4 \,atm$.