Question

The shape of $XeO{F}_4$ by VSEPR theory is:

• A. Trigonal bipyramidal
• B. Square pyramidal
• C. Pentagonal planar
• D. Octahedral

Answer 1

Answer: (B)

$s{p}^3{d}^2$ hybridization

4 B.P + 1 B.P (Doubly bonded) + 1 L.P

Square pyramidal



Oxygen atom doubly bonded to Xe lone pair of electrons on axial position.