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Question
Chemistry
The shape of XeOF4 by VSEPR theory is:
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Q. The shape of $XeOF_{4}$ by VSEPR theory is:
NTA Abhyas
NTA Abhyas 2020
Chemical Bonding and Molecular Structure
A
Trigonal bipyramidal
18%
B
Square pyramidal
64%
C
Pentagonal planar
0%
D
Octahedral
18%
Solution:
$sp^{3}d^{2}$ hybridization
4 B.P + 1 B.P (Doubly bonded) + 1 L.P
Square pyramidal
Oxygen atom doubly bonded to Xe lone pair of electrons on axial position.