The set of oxidation numbers of nitrogen in ammonium nitrate is

Question

The set of oxidation numbers of nitrogen in ammonium nitrate is (A)  -3,+3  (B)  -1,+1  (C)  +1,-1  (D)  -3,+5

Tardigrade Admin · Accepted Answer

NH4NO3NH4++NO3- Let the oxidation number of N is x . In NH4+ x+4=1 x=1-4=-3 In NO3- x+3(-2)=-1 x-6=-1 x=-1+6 =+5 Hence, the set of oxidation number of nitrogen in ammonium nitrate is -3,+5 .

Q. The set of oxidation numbers of nitrogen in ammonium nitrate is

$- 3, + 3$

$- 1, + 1$

$+ 1, - 1$

$- 3, + 5$

$N H_{4} N O_{3} N H_{4}^{+} + N O_{3}^{-}$ Let the oxidation number of N is $x$ . In $N H_{4}^{+}$ $x + 4 = 1$ $x = 1 - 4 = - 3$ In $N O_{3}^{-}$ $x + 3 (- 2) = - 1$ $x - 6 = - 1$ $x = - 1 + 6$ $= + 5$ Hence, the set of oxidation number of nitrogen in ammonium nitrate is $- 3, + 5$ .

Q. The set of oxidation numbers of nitrogen in ammonium nitrate is

−3,+3

−1,+1

+1,−1

−3,+5

NH4​NO3​NH4+​+NO3−​ Let the oxidation number of N is x . In NH4+​ x+4=1 x=1−4=−3 In NO3−​ x+3(−2)=−1 x−6=−1 x=−1+6 =+5 Hence, the set of oxidation number of nitrogen in ammonium nitrate is −3,+5 .

$- 3, + 3$

$- 1, + 1$

$+ 1, - 1$

$- 3, + 5$

$N H_{4} N O_{3} N H_{4}^{+} + N O_{3}^{-}$ Let the oxidation number of N is $x$ . In $N H_{4}^{+}$ $x + 4 = 1$ $x = 1 - 4 = - 3$ In $N O_{3}^{-}$ $x + 3 (- 2) = - 1$ $x - 6 = - 1$ $x = - 1 + 6$ $= + 5$ Hence, the set of oxidation number of nitrogen in ammonium nitrate is $- 3, + 5$ .