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Q. The set of oxidation numbers of nitrogen in ammonium nitrate is

Rajasthan PETRajasthan PET 2004

Solution:

$ N{{H}_{4}}N{{O}_{3}}NH_{4}^{+}+NO_{3}^{-} $ Let the oxidation number of N is $ x $ . In $ NH_{4}^{+} $ $ x+4=1 $ $ x=1-4=-3 $ In $ NO_{3}^{-} $ $ x+3(-2)=-1 $ $ x-6=-1 $ $ x=-1+6 $ $ =+5 $ Hence, the set of oxidation number of nitrogen in ammonium nitrate is $ -3,+5 $ .