The resultant of two vectors, 3 unit along east and 4 unit along north is

Question

The resultant of two vectors, 3 unit along east and 4 unit along north is (A) 2 unit (B) 3 unit (C) 5 unit (D) 1 unit

Tardigrade Admin · Accepted Answer

AB = 3 unit along east BC = 4 unit along north Resultant of two vectors is AC = AB + BC (By triangle law) The magnitude of AC is AC = √AB2 + BC2 = √(3)2 + (4)2 = √25 = 5 unit

Q. The resultant of two vectors, 3 unit along east and 4 unit along north is

2 unit

3 unit

5 unit

1 unit

$A B$ = 3 unit along east
$BC$ = 4 unit along north
Resultant of two vectors is $A C = A B + BC$ (By triangle law)
The magnitude of $A C$ is $A C = A B^{2} + B C^{2} = (3)^{2} + (4)^{2} = 25$ = 5 unit

Q. The resultant of two vectors, 3 unit along east and 4 unit along north is

2 unit

3 unit

5 unit

1 unit

AB = 3 unit along east BC = 4 unit along north Resultant of two vectors is AC=AB+BC (By triangle law) The magnitude of AC is AC=AB2+BC2​=(3)2+(4)2​=25​ = 5 unit

$A B$ = 3 unit along east
$BC$ = 4 unit along north
Resultant of two vectors is $A C = A B + BC$ (By triangle law)
The magnitude of $A C$ is $A C = A B^{2} + B C^{2} = (3)^{2} + (4)^{2} = 25$ = 5 unit