Q. The resultant of two vectors, 3 unit along east and 4 unit along north is
Motion in a Plane
Solution:
$\overrightarrow{AB} $ = 3 unit along east
$\overrightarrow{BC} $ = 4 unit along north
Resultant of two vectors is $\overrightarrow{AC} = \overrightarrow{AB} + \overrightarrow{BC} $ (By triangle law)
The magnitude of $\overrightarrow{AC}$ is $AC = \sqrt{AB^2 + BC^2} = \sqrt{(3)^2 + (4)^2} = \sqrt{25} $ = 5 unit
