The resonance frequency of the tank circuit of an oscillator when L=(10/π 2)mH and C=0.04 text μ F are connected in parallel is

Question

The resonance frequency of the tank circuit of an oscillator when L=(10/π 2)mH and C=0.04 text μ F are connected in parallel is (A) 250 kHz (B) 25 kHz (C) 2.5 kHz (D) 25 MHz

Tardigrade Admin · Accepted Answer

In parallel resonant circuit resonance frequency fo=(1/2π √LC)=(1/2π √(10× 10-3)π 2× 0.04× 10-6) =(104/2× 0.2)=25 kHz

Q. The resonance frequency of the tank circuit of an oscillator when $L = \frac{10}{π ^{2}} m H$ and $C = 0.04 μ F$ are connected in parallel is

250 kHz

25 kHz

2.5 kHz

25 MHz

2.5MHz

In parallel resonant circuit resonance frequency
$f_{o} = \frac{1}{2 π L C} = \frac{1}{2 π \frac{10 \times 10 ^{- 3}}{π ^{2}} \times 0.04 \times 10 ^{- 6}}$
$= \frac{10 ^{4}}{2 \times 0.2} = 25 k Hz$

Q. The resonance frequency of the tank circuit of an oscillator when L=π210​mH and C=0.04μF are connected in parallel is