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Q. The resonance frequency of the tank circuit of an oscillator when $ L=\frac{10}{{{\pi }^{2}}}mH $ and $ C=0.04\text{ }\mu F $ are connected in parallel is

KEAMKEAM 2008Alternating Current

Solution:

In parallel resonant circuit resonance frequency
$ {{f}_{o}}=\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{\frac{10\times {{10}^{-3}}}{{{\pi }^{2}}}\times 0.04\times {{10}^{-6}}}} $
$ =\frac{{{10}^{4}}}{2\times 0.2}=25\,kHz $