The relative velocity of two consecutive layer is 8 cm/s. If the perpendicular distance between the layers is 0.1 m, then the velocity gradient will be

Question

The relative velocity of two consecutive layer is 8 cm/s. If the perpendicular distance between the layers is 0.1 m, then the velocity gradient will be (A)  50 text s-1  (B)  text60 s-1  (C)  text75 s-1  (D)  text80 s-1

Tardigrade Admin · Accepted Answer

Velocity gradient =(Δ v/Δ y) where Δ v is relative velocity between the layers and Δ y is distance between the layers. Therefore velocity gradient =(8.0/0.1)=80.0 s-1

Q. The relative velocity of two consecutive layer is $8 c m / s$ . If the perpendicular distance between the layers is $0.1 m$ , then the velocity gradient will be

$50 s^{- 1}$

$60 s^{- 1}$

$75 s^{- 1}$

$80 s^{- 1}$

Velocity gradient $= \frac{Δ v}{Δ y}$
where $Δ v$ is relative velocity between the layers and $Δ y$ is distance between the layers.
Therefore velocity gradient $= \frac{8.0}{0.1} = 80.0 s^{- 1}$

Q. The relative velocity of two consecutive layer is 8cm/s. If the perpendicular distance between the layers is 0.1m, then the velocity gradient will be

50s−1

60 s−1

75 s−1

80 s−1