The relative density of a metal may be found by hanging a block of the metal from a spring balance and nothing that in air, the balance reads (5.00 ± 0.05) N while in water, it reads (4.00 ± 0.05) N. The relative density would be quoted as:

Question

The relative density of a metal may be found by hanging a block of the metal from a spring balance and nothing that in air, the balance reads (5.00 ± 0.05) N while in water, it reads (4.00 ± 0.05) N. The relative density would be quoted as: (A) 5.00 ± 0.05 (B) 5.00 ± 11 % (C) 5.00 ± 0.10 (D) 5.00 ± 6 %

Tardigrade Admin · Accepted Answer

text Relative density =( text Weight in air / text Loss of weight in water ) P=(5.00/1.00)=5.00 (d P/P)=(0.05/5.00)+(0.1/1.00)=0.11=11 % P=5.00 ± 11 %

Q. The relative density of a metal may be found by hanging a block of the metal from a spring balance and nothing that in air, the balance reads $(5.00 \pm 0.05) N$ while in water, it reads $(4.00 \pm 0.05) N$ . The relative density would be quoted as:

$5.00 \pm 0.05$

$5.00 \pm 11%$

$5.00 \pm 0.10$

$5.00 \pm 6%$

$Relative density = \frac{Weight in air}{Loss of weight in water}$
$P = \frac{5.00}{1.00} = 5.00$
$\frac{d P}{P} = \frac{0.05}{5.00} + \frac{0.1}{1.00} = 0.11 = 11%$
$P = 5.00 \pm 11%$

Q. The relative density of a metal may be found by hanging a block of the metal from a spring balance and nothing that in air, the balance reads (5.00±0.05)N while in water, it reads (4.00±0.05)N. The relative density would be quoted as:

5.00±0.05

5.00±11%

5.00±0.10

5.00±6%