The relationship between standard reduction potential of cell (in volts) and equilibrium constant at 25° C is shown by E text cell °=(5.91 × 10- x / n ) log 10 K. The value of ' X ' is.

Question

The relationship between standard reduction potential of cell (in volts) and equilibrium constant at 25° C is shown by E text cell °=(5.91 × 10- x / n ) log 10 K. The value of ' X ' is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

E text cell °=(0.0591/ n ) log 10 K =(5.91 × 10-2/ n ) log 10 K ∴ X =2

Q. The relationship between standard reduction potential of cell (in volts) and equilibrium constant at $2 5^{\circ} C$ is shown by $E_{cell}^{\circ} = \frac{5.91 \times 1 0 ^{- x}}{n} lo g_{10} K$ . The value of ' $X$ ' is________.

$E_{cell}^{\circ} = \frac{0.0591}{n} lo g_{10} K = \frac{5.91 \times 1 0 ^{- 2}}{n} lo g_{10} K$
$∴ X = 2$

Q. The relationship between standard reduction potential of cell (in volts) and equilibrium constant at 25∘C is shown by Ecell ∘​=n5.91×10−x​log10​K. The value of ' X ' is________.

Ecell ∘​=n0.0591​log10​K=n5.91×10−2​log10​K ∴X=2

Q. The relationship between standard reduction potential of cell (in volts) and equilibrium constant at $2 5^{\circ} C$ is shown by $E_{cell}^{\circ} = \frac{5.91 \times 1 0 ^{- x}}{n} lo g_{10} K$ . The value of ' $X$ ' is________.

$E_{cell}^{\circ} = \frac{0.0591}{n} lo g_{10} K = \frac{5.91 \times 1 0 ^{- 2}}{n} lo g_{10} K$
$∴ X = 2$