Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The relationship between standard reduction potential of cell (in volts) and equilibrium constant at $25^{\circ} C$ is shown by $E _{\text {cell }}^{\circ}=\frac{5.91 \times 10^{- x }}{ n } \log _{10} K$. The value of ' $X$ ' is________.

Electrochemistry

Solution:

$E _{\text {cell }}^{\circ}=\frac{0.0591}{ n } \log _{10} K =\frac{5.91 \times 10^{-2}}{ n } \log _{10} K$
$\therefore X =2$