Question

The relationship between Gibbs' free energy change $(\Delta G)$ and emf $(E)$ of a reversible electrochemical cell is given by

• A. $\Delta G=nFE$
• B. $\Delta G=nF/E$
• C. $\Delta G=-nFE$
• D. $\Delta G=E/nF$

Answer 1

Answer: (C)

The Gibb's free energy change $\Delta G$ and emf $\left(E^o\right)$ of a reversible electrochemical cell are related by the following expression.
$\Delta G=-nF{E}_{\text{cell }}^o$ or $=-nFE$