Question

The relationship between Gibbs' free energy change $(\Delta G)$ and emf $(E)$ of a reversible electrochemical cell is given by

• A. $ \Delta G=nFE $
• B. $ \Delta G=nF/E $
• C. $ \Delta G=-nFE $
• D. $ \Delta G=E/nF $

Answer 1

Answer: (C)

The Gibb's free energy change $\Delta G$ and emf $\left(E^{o}\right)$ of a reversible electrochemical cell are related by the following expression.
$\Delta G=-n F E_{\text {cell }}^{o}$ or $=-n F E$