The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively

Question

The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively (A) redox reaction ; -3 and -5 (B) redox reaction ; +3 and +5 (C) disproportionation reaction ; -3 and +1 (D) disproportionation reaction ; -3 and +3

Tardigrade Admin · Accepted Answer

Disproportionation reaction is a reaction in which the same element gets oxidized and gets reduced from one initial oxidation state.
Step 1: Write down the reaction:

P_{4 (white)} + N a O H \to P H_{3} + N a H_{2} P O_{2}

Step 2: Calculate the oxidation state of phosphorous in the various phosphorous compounds:
Let the oxidation number of

P

be

x

in each case

P_{4} \to 4 x = 0 ⟹ x = 0

P H_{3} \to x + 3 = 0 ⟹ x = - 3

N a H_{2} P O_{2} \to + 1 + 2 + x - 4 = 0 ⟹ x = + 1

Q. The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively

redox reaction ; -3 and -5

redox reaction ; +3 and +5

disproportionation reaction ; -3 and +1

disproportionation reaction ; -3 and +3

Q. The reaction of white phosphorus with aqueous $N a O H$ gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively