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  4. The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively

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Q. The reaction of white phosphorus with aqueous $NaOH$ gives phosphine along with another phosphorus containing compound. The reaction type ; the oxidation states of phosphorus in phosphine and the other product are respectively

The p-Block Elements - Part2

Solution:

Disproportionation reaction is a reaction in which the same element gets oxidized and gets reduced from one initial oxidation state.
Step 1: Write down the reaction:
$P _{4 \text { (white) }}+ NaOH \rightarrow PH _{3}+ NaH _{2} PO _{2}$
Step 2: Calculate the oxidation state of phosphorous in the various phosphorous compounds:
Let the oxidation number of $P$ be $x$ in each case
$P _{4} \rightarrow 4 x =0 \Longrightarrow x =0$
$PH _{3} \rightarrow x +3=0 \Longrightarrow x =-3$
$NaH _{2} PO _{2} \rightarrow+1+2+ x -4=0 \Longrightarrow x =+1$