The reaction of white phosphorous with aqueous NaOH gives phosphine along with another phosphorous containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are respectively

Question

The reaction of white phosphorous with aqueous NaOH gives phosphine along with another phosphorous containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are respectively (A) redox reaction; -3 and -5 (B) redox reaction; +3 and +5 (C) disproportionation reaction; -3 and +5 (D) disproportionation reaction; -3 and +3

Tardigrade Admin · Accepted Answer

The balanced disproportionation reaction involving white phosphorus with aq.

N a O H

is

*However, as the option involving +1 oxidation state is completely missing, one might consider that

N a H_{2} P O_{2}

formed has undergone thermal decomposition as shown below:

2 N a H_{2} P O_{2} ⟶ Δ N a_{2} H P O_{4} + P H_{3}

Although heating is nowhere mentioned in the question, the "other product" as per available options seems to be

N a_{2} H P O_{4}

(oxidation state

= + 5

).

Q. The reaction of white phosphorous with aqueous NaOH gives phosphine along with another phosphorous containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are respectively

redox reaction; -3 and -5

redox reaction; +3 and +5

disproportionation reaction; -3 and +5

disproportionation reaction; -3 and +3

Q. The reaction of white phosphorous with aqueous $N a O H$ gives phosphine along with another phosphorous containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are respectively